At the local video rental store, José rents two movies and three games?
At the local video rental store, José rents two movies and three games for a total of $15.50. At the same time, Meg rents three movies and one game for a total of $12.05. How much money is needed to rent a combination of one game and one movie?
Public Comments
- Why don't you figure out your homework yourself hun?
- one movie = x one game = y 2x + 3y = 15.50 3x + y = 12.05 If we multiply the second equation by 3... 2x+3y = 15.50 9x+3y = 36.15 Subtract the equations leaving... -7x = -20.65 x = 2.95 2(2.95) + 3y = 15.50 5.90 + 3y = 15.50 3y = 9.6 y = 3.20 One movie costs $2.95 One game costs $3.20 (One movie + One game) costs $6.15
- x= movies y= games Using substitution... 2x+3y=15.5 3x+1y=12.05 Multiply the second equation by 3 2x+3y=15.5 -9x+3y=36.15 -7x=-20.15 x=2.95 thus, movies cost $2.95 plug that in for either equation to figure out games.
Powered by Yahoo! Answers